PLEASE HELP! THANK YOU!A computer was originally purchased for $900 and undergoes a 14% annual depreciation rate. The computer is now worth $364. The number of years that have passed, t, since the computer was purchased can be found using the following equation:364 = 900(1 − 0.14)tSolve the equation by graphing to determine how many years have passed since the computer was purchased. Round to the nearest whole year.t = ______ years

Answer is 6

------------------------------------------------------------------

Work Shown:

[tex]364 = 900(1-0.14)^t[/tex]

[tex]364 = 900(0.86)^t[/tex]

[tex]\frac{364}{900} = 0.86^t[/tex]

[tex]\frac{91}{225} = 0.86^t[/tex]

[tex]\log\left(\frac{91}{225}\right) = \log\left(0.86^t\right)[/tex]

[tex]-0.39314112579027 \approx t*\log\left(0.86\right)[/tex]

[tex]-0.39314112579027 \approx t*\left(-0.06550154875643\right)[/tex]

[tex]\frac{-0.39314112579027}{-0.06550154875643} \approx t[/tex]

[tex]6.0020126738099 \approx t[/tex]

[tex]t \approx 6.0020126738099[/tex]

which rounds to 6 when rounding to the nearest whole number

So it takes roughly 6 years for the value to go from $900 to $364